solve the following quadratics by factoring
x^2=6x
x^2=6x-8
6x^2-13x+6=0
5x^2-17x+14=0
12x^2+x=1
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solve the following quadratics by factoring
x^2=6x
x^2=6x-8
6x^2-13x+6=0
5x^2-17x+14=0
12x^2+x=1
Why dont you show us some work and we will critique you...for the first one I will give you thatQuote:
Originally Posted by gumi
for the 2nd one i got
(x-3)^2=1
is that right?
Yes that is correct...very good...but it can be simpler factor it intoQuote:
Originally Posted by gumi
Hello,
For the first one, do you really need to complete the square ? oO It's only asked to factorise ^^
x²=6x
x²-6x=0
x(x-6)=0
So...
But on another post of theirs it asked for completing the square so I just took the liberty of assuming that is what she meantQuote:
Originally Posted by Moo
the 3rd one i got
(2 + -3x)(3 + -2x) = 0
is that right?