solve the following quadratics by factoring

x^2=6x

x^2=6x-8

6x^2-13x+6=0

5x^2-17x+14=0

12x^2+x=1

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- Apr 13th 2008, 11:47 AMgumisolve quadratics by factoring
solve the following quadratics by factoring

x^2=6x

x^2=6x-8

6x^2-13x+6=0

5x^2-17x+14=0

12x^2+x=1 - Apr 13th 2008, 11:49 AMMathstud28Ok
- Apr 13th 2008, 12:05 PMgumi
for the 2nd one i got

(x-3)^2=1

is that right? - Apr 13th 2008, 12:07 PMMathstud28Haha
- Apr 13th 2008, 12:08 PMMoo
Hello,

For the first one, do you really need to complete the square ? oO It's only asked to factorise ^^

x²=6x

x²-6x=0

x(x-6)=0

So... - Apr 13th 2008, 12:09 PMMathstud28yeah I know
- Apr 13th 2008, 12:25 PMgumi
the 3rd one i got

(2 + -3x)(3 + -2x) = 0

is that right?