solve the following quadratics by factoring

x^2=6x

x^2=6x-8

6x^2-13x+6=0

5x^2-17x+14=0

12x^2+x=1

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- April 13th 2008, 10:47 AMgumisolve quadratics by factoring
solve the following quadratics by factoring

x^2=6x

x^2=6x-8

6x^2-13x+6=0

5x^2-17x+14=0

12x^2+x=1 - April 13th 2008, 10:49 AMMathstud28Ok
- April 13th 2008, 11:05 AMgumi
for the 2nd one i got

(x-3)^2=1

is that right? - April 13th 2008, 11:07 AMMathstud28Haha
- April 13th 2008, 11:08 AMMoo
Hello,

For the first one, do you really need to complete the square ? oO It's only asked to factorise ^^

x²=6x

x²-6x=0

x(x-6)=0

So... - April 13th 2008, 11:09 AMMathstud28yeah I know
- April 13th 2008, 11:25 AMgumi
the 3rd one i got

(2 + -3x)(3 + -2x) = 0

is that right?