x^2 + 4y^2=20 and x+2y=6

I solved for y and set them equal to each other but the x's cancel out. What else could I do?

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- Apr 10th 2008, 09:10 PMMathNeedy18Point of intersection
x^2 + 4y^2=20 and x+2y=6

I solved for y and set them equal to each other but the x's cancel out. What else could I do? - Apr 10th 2008, 09:12 PMMathstud28Hmm
- Apr 10th 2008, 09:15 PMMathNeedy18
- Apr 10th 2008, 09:21 PMTheEmptySet