Use synthetic division to divide g(x)=x^3-17x^2+90x-144 by x-8. Use the result to find all zeros of g.

I got x^2-9x+12 for the quotient with -48 remainder.

Is this correct?

The problem is, how am I supposed to find all zeros when the divisor I am expected to use has a remainder? By the way the question is worded, do you think I am supposed to find a divisor that works?