if it helps anyone, i set a new axis to (0,0) and solved for y=AX^2 where y= drop in my case -40.383 (14.617-55). i let its y' = 3.21609 and got x = in terms of A. used that in y=AX^2 and got A. (3.21609^2)/4A = -40.383, a's cancel. then used y=AX^2 + BX +C and y' = 2AX + B where x was 45 and A was found value. this got B. then i used y=AX^2 + BX +C where y = 55 and x = -B/2A and got C!!!
final equation = -0.064x^2 + 8.98X -259.773