f(x)=square root x+2 then outside the square root -3. Can someone help explain how to graph this and also whats being done to this fuction y=-2f(x+3)-1 Thanks for the help.
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Originally Posted by av8or91 f(x)=square root x+2 then outside the square root -3. Can someone help explain how to graph this and also whats being done to this fuction y=-2f(x+3)-1 Thanks for the help. so lets start with the basic function Then This shifts the graph two units to the left on the x axis. finally the + 3 shifts the graph up 3 units in the y direction. see the attached graph. This should help with the second part as well
the problem says -3 so would that just shift it down 3 units then?
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