1. ## Graphing Function Question

f(x)=square root x+2 then outside the square root -3.

Can someone help explain how to graph this and also whats being done to this fuction y=-2f(x+3)-1

Thanks for the help.

2. Originally Posted by av8or91
f(x)=square root x+2 then outside the square root -3.

Can someone help explain how to graph this and also whats being done to this fuction y=-2f(x+3)-1

Thanks for the help.

so lets start with the basic function $h(x) =\sqrt{x}$

Then $h(x+2)=\sqrt{x+2}$ This shifts the graph two units to the left on the x axis.

finally $f(x)=h(x+2)+3$ the + 3 shifts the graph up 3 units in the y direction.

see the attached graph.

This should help with the second part as well

3. the problem says -3 so would that just shift it down 3 units then?