Thread: Graphing Function Question

f(x)=square root x+2 then outside the square root -3.


Can someone help explain how to graph this and also whats being done to this fuction y=-2f(x+3)-1

Thanks for the help.

Originally Posted by av8or91

f(x)=square root x+2 then outside the square root -3.


Can someone help explain how to graph this and also whats being done to this fuction y=-2f(x+3)-1

Thanks for the help.

so lets start with the basic function

Then This shifts the graph two units to the left on the x axis.

finally the + 3 shifts the graph up 3 units in the y direction.

see the attached graph.

This should help with the second part as well

the problem says -3 so would that just shift it down 3 units then?