log(x+2)=log(5x-3)
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Originally Posted by J_Pettway log(x+2)=log(5x-3) Exponentiate both sides with respect to base 10. This way, the logs will cancel out because $\displaystyle 10^{\log(\text{JUNK})} = \text{JUNK}$ $\displaystyle x+2=5x-3$ $\displaystyle 4x = 5$ $\displaystyle x = 1.25$
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