# solve the logarithmic equation

• March 31st 2008, 05:35 AM
J_Pettway
solve the logarithmic equation
log(x+2)=log(5x-3)
• March 31st 2008, 05:46 AM
colby2152
Quote:

Originally Posted by J_Pettway
log(x+2)=log(5x-3)

Exponentiate both sides with respect to base 10. This way, the logs will cancel out because $10^{\log(\text{JUNK})} = \text{JUNK}$

$x+2=5x-3$

$4x = 5$

$x = 1.25$