help me solve the logarithms expression log2 (8/x)
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Originally Posted by chinashaw1@yahoo.com help me solve the logarithms expression log2 (8/x) Since $\displaystyle 8=2^3$ you can transform the given term: $\displaystyle \log_2\left(\frac8x\right)=\log_2\left(\frac{2^3}x \right)= \log_2(2^3) - \log_2(x)= 3-\log_2(x)$
log6 11+log6 x=1
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