Hello, please help me with the following questions:
Q1) For the function g(x)=x²-4x
Find in the simplest form g(a+1)
Q2) Find the equation of the line joining: (3,4) and (5,-3)
Q3) Factorise: 4t²-1
Q4) Solve: 3x²-x-5=0
Thanks
Hello, please help me with the following questions:
Q1) For the function g(x)=x²-4x
Find in the simplest form g(a+1)
Q2) Find the equation of the line joining: (3,4) and (5,-3)
Q3) Factorise: 4t²-1
Q4) Solve: 3x²-x-5=0
Thanks
are these homework problems?
write as x(x - 4)
now replace x with (a + 1) and simplify
the slope of the line passing through the points $\displaystyle (x_1,y_1)$ and $\displaystyle (x_2,y_2)$ are given by: $\displaystyle m = \frac {y_2 - y_1}{x_2 - x_1}$Q2) Find the equation of the line joining: (3,4) and (5,-3)
the equation of a line is of the form $\displaystyle y = mx + b$
you can find m using the above formula and then use one of the coordinates as the values of x and y. plug them in the equation of the line along with m and solve for b. or, if you prefer, you can use the point slope form: $\displaystyle y - y_1 = m(x - x_1)$. this gives the equation of the line with slope $\displaystyle m$ passing through the point $\displaystyle (x_1,y_1)$
write as (2t)^2 - 1Q3) Factorise: 4t²-1
this is the difference of two squares. factor accordingly
use the quadratic formula. you do remember it, right?Q4) Solve: 3x²-x-5=0