Hello, takkun0486!

Do you know the procedure for finding an inverse function?

[1] Replace the function withy.

[2] "Switch" the x's and y's.

[3] Solve for y.

We have:How would I find out the inverses for these functions?

"Switch":

Solve fory: .

Square: .

Then: .

Therefore: .

We have: .

Switch: .

Solve fory: .

Take logs: . y + 1)\ln(2) " alt="\ln(x - 4)\:=\:\ln(2^{y+1})\quad\Rightarrow\quad \ln(x - 4)\:=\y + 1)\ln(2) " />

Then: .

Therefore: .

We have: .

Switch: .

Solve fory: .

Take cube roots: .

Then: .

Therefore: . . . . or: