Thread: Vertexing question

Find/sketch vertex of the parabola y = x^2 + x – 30 (using -b/2a method)

Originally Posted by brad

Find/sketch vertex of the parabola y = x^2 + x – 30 (using -b/2a method)

Well, the axis of symmetry is the line , so where does this line intersect your parabola?

-Dan