Results 1 to 8 of 8

Math Help - I need help on my Pre Calc Worksheet?

  1. #1
    Junior Member
    Joined
    Mar 2008
    Posts
    35

    I need help on my Pre Calc Worksheet?

    1.) Find a number between 0 and 2pi such that the angle of 0 radians in standard position is coterminal with an angle of -(23pi/3) radians in standard position.

    2.) Provide the exact value of sec -(7pi/3)

    3.) if the terminal side of an angle of t radians in standard position passes through the point (-2,3), then find the following values: tant t, csc t, and cost t.

    4)Express as a single real number (cos -2pi/3 - 1)^2


    7. A wheel is 5.4 feet in diameter and rotates at 1700 rpm
    A.) what is the angular speed of the wheel?
    B.) How fast is a point on the circumference of the wheel traveling in feet per minute? in miles per hour?
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Forum Admin topsquark's Avatar
    Joined
    Jan 2006
    From
    Wellsville, NY
    Posts
    10,211
    Thanks
    419
    Awards
    1
    Quote Originally Posted by victorfk06 View Post
    2.) Provide the exact value of sec -(7pi/3)
    sec \left ( -\frac{7 \pi}{3} \right ) = sec \left ( -\frac{7 \pi}{3} + 2 \pi \right )

    = sec \left ( -\frac{\pi}{3} \right )

    = \frac{1}{cos \left ( -\frac{\pi}{3} \right ) }

    Can you take it from here?

    -Dan
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Forum Admin topsquark's Avatar
    Joined
    Jan 2006
    From
    Wellsville, NY
    Posts
    10,211
    Thanks
    419
    Awards
    1
    Quote Originally Posted by victorfk06 View Post
    3.) if the terminal side of an angle of t radians in standard position passes through the point (-2,3), then find the following values: tant t, csc t, and cost t.
    The angle will be in QII, so by applying the definitions:
    tan(t) = \frac{3}{-2}

    csc(t) = \frac{\sqrt{(-2)^2 + 3^3}}{3}

    cos(t) = \frac{-2}{\sqrt{(-2)^2 + 3^2}}

    -Dan
    Follow Math Help Forum on Facebook and Google+

  4. #4
    Forum Admin topsquark's Avatar
    Joined
    Jan 2006
    From
    Wellsville, NY
    Posts
    10,211
    Thanks
    419
    Awards
    1
    Quote Originally Posted by victorfk06 View Post
    4)Express as a single real number (cos -2pi/3 - 1)^2
    There are various and sundry ways to do this. The most obvious is
    \left ( cos \left ( -\frac{2 \pi}{3} \right ) - 1 \right ) ^2

    = \left ( -\frac{\sqrt{3}}{2} - 1 \right ) ^2

    = \left ( \frac{-\sqrt{3} - 2}{2} \right ) ^2

    Now square that.

    -Dan
    Follow Math Help Forum on Facebook and Google+

  5. #5
    Junior Member
    Joined
    Mar 2008
    Posts
    35
    thanks but i need help on others guys plz help thank you really appreciate it.
    Follow Math Help Forum on Facebook and Google+

  6. #6
    Junior Member
    Joined
    Mar 2008
    Posts
    35
    from # 2 i couldn't finish it what wuz the final fraction
    Follow Math Help Forum on Facebook and Google+

  7. #7
    Junior Member
    Joined
    Mar 2008
    Posts
    35
    from 2 it's equal to one right
    Follow Math Help Forum on Facebook and Google+

  8. #8
    Junior Member
    Joined
    Mar 2008
    Posts
    35
    from problem 3 the tan t= -2/3 right that's what i got when i drew the triangle. and the csc under the square it should be squared not cube right?
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Need help on this worksheet
    Posted in the Algebra Forum
    Replies: 3
    Last Post: April 6th 2011, 08:05 PM
  2. Minitab worksheet
    Posted in the Advanced Statistics Forum
    Replies: 0
    Last Post: April 30th 2010, 03:50 PM
  3. Worksheet with answers (and Solution??)
    Posted in the Statistics Forum
    Replies: 0
    Last Post: August 5th 2009, 03:08 PM
  4. A Worksheet of Epic Proportions
    Posted in the Math Topics Forum
    Replies: 1
    Last Post: March 11th 2008, 08:31 AM
  5. Hey, trouble on worksheet! help plz!
    Posted in the Calculus Forum
    Replies: 9
    Last Post: May 6th 2007, 04:48 PM

Search Tags


/mathhelpforum @mathhelpforum