# Math Help - I need help on my Pre Calc Worksheet?

1. ## I need help on my Pre Calc Worksheet?

1.) Find a number between 0 and 2pi such that the angle of 0 radians in standard position is coterminal with an angle of -(23pi/3) radians in standard position.

2.) Provide the exact value of sec -(7pi/3)

3.) if the terminal side of an angle of t radians in standard position passes through the point (-2,3), then find the following values: tant t, csc t, and cost t.

4)Express as a single real number (cos -2pi/3 - 1)^2

7. A wheel is 5.4 feet in diameter and rotates at 1700 rpm
A.) what is the angular speed of the wheel?
B.) How fast is a point on the circumference of the wheel traveling in feet per minute? in miles per hour?

2. Originally Posted by victorfk06
2.) Provide the exact value of sec -(7pi/3)
$sec \left ( -\frac{7 \pi}{3} \right ) = sec \left ( -\frac{7 \pi}{3} + 2 \pi \right )$

$= sec \left ( -\frac{\pi}{3} \right )$

$= \frac{1}{cos \left ( -\frac{\pi}{3} \right ) }$

Can you take it from here?

-Dan

3. Originally Posted by victorfk06
3.) if the terminal side of an angle of t radians in standard position passes through the point (-2,3), then find the following values: tant t, csc t, and cost t.
The angle will be in QII, so by applying the definitions:
$tan(t) = \frac{3}{-2}$

$csc(t) = \frac{\sqrt{(-2)^2 + 3^3}}{3}$

$cos(t) = \frac{-2}{\sqrt{(-2)^2 + 3^2}}$

-Dan

4. Originally Posted by victorfk06
4)Express as a single real number (cos -2pi/3 - 1)^2
There are various and sundry ways to do this. The most obvious is
$\left ( cos \left ( -\frac{2 \pi}{3} \right ) - 1 \right ) ^2$

$= \left ( -\frac{\sqrt{3}}{2} - 1 \right ) ^2$

$= \left ( \frac{-\sqrt{3} - 2}{2} \right ) ^2$

Now square that.

-Dan

5. thanks but i need help on others guys plz help thank you really appreciate it.

6. from # 2 i couldn't finish it what wuz the final fraction

7. from 2 it's equal to one right

8. from problem 3 the tan t= -2/3 right that's what i got when i drew the triangle. and the csc under the square it should be squared not cube right?