2tanx/(1-(tan(x)^2) + 1/2(cosx^2)-1 = cosx+sinx/cosx-sinx
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Originally Posted by bilbobaggins 2tanx/(1-(tan(x)^2) + 1/2(cosx^2)-1 = cosx+sinx/cosx-sinx Will you please rewrite this using parenthesis so we can see what the actual problem is? -Dan
Hello, bilbobaggins! I think I've guessed what you meant . . . We need a number of double-angle identities: . . . . . . The left side is: . Since , the numerator becomes: . . The fraction becomes: .
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