The equation of circle A is (x-4)2+(y-2)2=16 and the equation of circle B is (x+6)2+(y+3)2=9. what is the distance between the centers of these circles?
the equation of circle P is (x-3)2+(y+2)2=34 and equation of circle Q is (x-4)2+(y+5)=52 What is the distance between the centers of these circles?
And Use the distance formula to find the distance between the 2 centers. But I dont understand how.
its the square root of (x2-x) to the second + (y2-y)to the second. HELP!!!
The first circle has a center at (4, 2). The second circle has a center at (-6, -3).
The distance between any two points $\displaystyle (x_1, y_1)$ and $\displaystyle (x_2, y_2)$ is
$\displaystyle \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$
Can you take it from here?
-Dan