The equation of circle A is (x-4)2+(y-2)2=16 and the equation of circle B is (x+6)2+(y+3)2=9. what is the distance between the centers of these circles?

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- Mar 16th 2008, 12:00 PMjwein4492quation of a circle
The equation of circle A is (x-4)2+(y-2)2=16 and the equation of circle B is (x+6)2+(y+3)2=9. what is the distance between the centers of these circles?

- Mar 16th 2008, 12:07 PMgalactus
One is centered at (4,2) and the other at (-6,-3).

Use the distance formula and see. - Mar 16th 2008, 12:07 PMtopsquark
- Mar 16th 2008, 12:16 PMjwein4492thanks now I have one that is
the equation of circle P is (x-3)2+(y+2)2=34 and equation of circle Q is (x-4)2+(y+5)=52 What is the distance between the centers of these circles?

And Use the distance formula to find the distance between the 2 centers. But I dont understand how.

its the square root of (x2-x) to the second + (y2-y)to the second. HELP!!! - Mar 16th 2008, 12:23 PMtopsquark
The first circle has a center at (4, 2). The second circle has a center at (-6, -3).

The distance between any two points $\displaystyle (x_1, y_1)$ and $\displaystyle (x_2, y_2)$ is

$\displaystyle \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Can you take it from here?

-Dan - Mar 16th 2008, 12:31 PMjwein4492No
I dont understandn the square root stuff.

- Mar 16th 2008, 12:34 PMtopsquark
- Mar 16th 2008, 12:37 PMjwein4492yes
yes on simplifying the answer and showing my work on it?

my teacher is really hard to understand and doesnt explain very well. - Mar 16th 2008, 12:40 PMtopsquark
- Mar 16th 2008, 12:44 PMjwein4492cool
thanks so much i am sure we will talk again.