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**mathlete** The period, T, of a pendulum of length L is given by the following equation where g is the acceleration constant due to gravity.

T = (2pi)sqrt(L/g)

(a) Suppose the length of the pendulum changes by L. How will the period change? Express your answer in terms of T and L only.

deltaT = (T/2L)deltaL

(b) If the length of the pendulum increases by 2%, by what percent does the period change?

???

ok so i figured out part a) that was cake...sort of...well not really, anyways i need help on doing part b) thanks

mathlete