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Math Help - pendulum

  1. #1
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    pendulum

    The period, T, of a pendulum of length L is given by the following equation where g is the acceleration constant due to gravity.

    T = (2pi)sqrt(L/g)


    (a) Suppose the length of the pendulum changes by L. How will the period change? Express your answer in terms of T and L only.

    deltaT = (T/2L)deltaL

    (b) If the length of the pendulum increases by 2%, by what percent does the period change?

    ???

    ok so i figured out part a) that was cake...sort of...well not really, anyways i need help on doing part b) thanks

    mathlete
    Last edited by mathlete; March 12th 2008 at 05:05 PM.
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  2. #2
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    Quote Originally Posted by mathlete View Post
    The period, T, of a pendulum of length L is given by the following equation where g is the acceleration constant due to gravity.

    T = (2pi)sqrt(L/g)


    (a) Suppose the length of the pendulum changes by L. How will the period change? Express your answer in terms of T and L only.

    deltaT = (T/2L)deltaL

    (b) If the length of the pendulum increases by 2%, by what percent does the period change?

    ???

    ok so i figured out part a) that was cake...sort of...well not really, anyways i need help on doing part b) thanks

    mathlete
    \frac{\Delta L}{L} = 0.02

    So \Delta L = 0.02L

    and
    \Delta T \approx \left ( \frac{T}{2L} \right ) ~ \Delta L
    and then change that into a percent change in T.

    -Dan
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