The period, T, of a pendulum of length L is given by the following equation where g is the acceleration constant due to gravity.
T = (2pi)sqrt(L/g)
(a) Suppose the length of the pendulum changes by L. How will the period change? Express your answer in terms of T and L only.
deltaT = (T/2L)deltaL
(b) If the length of the pendulum increases by 2%, by what percent does the period change?
ok so i figured out part a) that was cake...sort of...well not really, anyways i need help on doing part b) thanks