how do I draw this? What method can I use?
Q: Plot the graph of y=3(x+2)squared -3 for the domain -5<x<2 and determine the following:
1.1 Turning point
1.2 Axis of symmetry
1.3 x-intercepts
1.4 y-intercepts
1.5 domain
1.6 Range
how do I draw this? What method can I use?
Q: Plot the graph of y=3(x+2)squared -3 for the domain -5<x<2 and determine the following:
1.1 Turning point
1.2 Axis of symmetry
1.3 x-intercepts
1.4 y-intercepts
1.5 domain
1.6 Range
. With such a form of the equation of a parabola you can get all necessary values.
1.1 Turning point: V(-2, -3)
1.2 Axis of symmetry: x = -2. The parabola opens upward (3>0) and is stretched(?) by the factor 3.
1.3 x-intercepts:
1.4 y-intercepts:
1.5 domain: given:
1.6 Range: see coordinates of vertex.
, . Therefore
Therefore the range is r = (-3;45)