First, hello all. Great I found this forum.

Please help me solve this mistery

.

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we have two vertices:

A(1,1)

B(0,2)

and there is also a circle K:

K: (x-5)^2 + (x-5)^2 = 16

Now I have to find a circle G: (x-a)^2 + (x-b)^2 = r^2

This circle (G) has to:

- have both vertices (A and B) on its edge

- "touch" the circle K in only one vertex

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Here are the answers:

G1: (x-1)^2 + (x-2)^2 = 1

G2: (x-4)^2 + (x-5)^2 = 25

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I have the answers all right, however I don't know how to calculate them.

Please help me find a way to calculate the answers.

And excuse my english, because I am not very familiar with english mathematical terminology.

Thank you,

UFOKatarn