Hello,Originally Posted byOverclockerR520

to speed up with your hectic week:

length of rectangle : l

width of rectangle : w

area of rectangle : w*l

Part of the perimeter which consists of wire = 2w +l = 32'

That means l = 32'-2w

You get the area with respect to w:

Let the first derivative be zero and you'll get: w = 8', thus l = 16'

Maximal area = 128 sqrft.

Greetings

EB