Hello,Originally Posted by OverclockerR520
to speed up with your hectic week:
length of rectangle : l
width of rectangle : w
area of rectangle : w*l
Part of the perimeter which consists of wire = 2w +l = 32'
That means l = 32'-2w
You get the area with respect to w:
Let the first derivative be zero and you'll get: w = 8', thus l = 16'
Maximal area = 128 sqrft.