Find the domain of f(x)=1/(x-2)^2 algebraically. Anyone that can help me quick thanks!
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$\displaystyle f(x) = \frac{1}{(x-2)^2}$ The denominator can't be 0. $\displaystyle (x-2)^2=0$ $\displaystyle x=2$ The domain is $\displaystyle \mathbb{R} - \{2\}$.
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