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Math Help - Anyone help with these 2 problems?

  1. #1
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    Anyone help with these 2 problems?

    1. Sketch the graph of the equation 2y + 3x = 1. Help with Steps Please? Anyone?

    2. Determine the equation of the straight line through the point (-1, 5) with slope m = -1. Steps?
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  2. #2
    Super Member wingless's Avatar
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    "1. Sketch the graph of the equation 2y + 3x = 1"

    As this equation represents a line, finding two points and drawing the line through them will be enough. I would find the points where the line crosses the axes.

    2y + 3x = 1

    If I take y=0,
    the equation will be, 0 + 3x = 1,
    x=\frac{1}{3}
    So the point is \left(\frac{1}{3},0\right)

    Similarly, If I take x=0,
    the equation becomes, 2y + 0 = 1,
    y=\frac{1}{2}
    So the point is \left(0,\frac{1}{2}\right)

    Now you can draw the axes, put the points and draw the line that passes on them.






    "2. Determine the equation of the straight line through the point (-1, 5) with slope m = -1."

    The general equation of line is y = m\cdot x + C. m is the slope of the line and C is a constant. Now, using the information given in the question, try to find C. Then there you found the equation
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  3. #3
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    Quote Originally Posted by dude View Post
    2. Determine the equation of the straight line through the point (-1, 5) with slope m = -1. Steps?
    The equation of a line with m that passes with (x₁, y₁):
    y - y₁ = m (x - x₁)

    So: y 5 = -1 (x + 1)
    y = 4 - x
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