# Thread: Anyone help with these 2 problems?

1. ## Anyone help with these 2 problems?

1. Sketch the graph of the equation 2y + 3x = 1. Help with Steps Please? Anyone?

2. Determine the equation of the straight line through the point (-1, 5) with slope m = -1. Steps?

2. "1. Sketch the graph of the equation 2y + 3x = 1"

As this equation represents a line, finding two points and drawing the line through them will be enough. I would find the points where the line crosses the axes.

$\displaystyle 2y + 3x = 1$

If I take $\displaystyle y=0$,
the equation will be, $\displaystyle 0 + 3x = 1$,
$\displaystyle x=\frac{1}{3}$
So the point is $\displaystyle \left(\frac{1}{3},0\right)$

Similarly, If I take $\displaystyle x=0$,
the equation becomes, $\displaystyle 2y + 0 = 1$,
$\displaystyle y=\frac{1}{2}$
So the point is $\displaystyle \left(0,\frac{1}{2}\right)$

Now you can draw the axes, put the points and draw the line that passes on them.

"2. Determine the equation of the straight line through the point (-1, 5) with slope m = -1."

The general equation of line is $\displaystyle y = m\cdot x + C$. m is the slope of the line and C is a constant. Now, using the information given in the question, try to find C. Then there you found the equation

3. Originally Posted by dude
2. Determine the equation of the straight line through the point (-1, 5) with slope m = -1. Steps?
The equation of a line with m that passes with (x₁, y₁):
y - y₁ = m (x - x₁)

So: y – 5 = -1 (x + 1)
y = 4 - x