hi agian!
how do you fine the coorrdinates where the line $\displaystyle 2x+3y=1$ meets the curve $\displaystyle x(x-y) = 2 $
kind regards
dadon
Solve $\displaystyle 2x+3y=1$ for y, plug this y value into $\displaystyle x(x-y) = 2 $, and solve the resulting equation for x. The use these x values in either of the original equations to get the corresponding y values. I got (6/5, -7/15) and (-1, 1).Originally Posted by dadon
-Dan
Rewrite the first equation asOriginally Posted by dadon
$\displaystyle y=\frac{1-2x}{3}$
Then substitute this for $\displaystyle y$ in the second equation:
$\displaystyle x(x-\frac{1-2x}{3}) = 2 $
and solve for $\displaystyle x$.
Then substitute the value/s of $\displaystyle x$ that you have
found back into one of the equations and solve for $\displaystyle y$.
RonL