Results 1 to 6 of 6

Math Help - line meeting curve.

  1. #1
    Member
    Joined
    Apr 2006
    Posts
    201
    Awards
    1

    Post line meeting curve.

    hi agian!

    how do you fine the coorrdinates where the line 2x+3y=1 meets the curve x(x-y) = 2

    kind regards

    dadon
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Forum Admin topsquark's Avatar
    Joined
    Jan 2006
    From
    Wellsville, NY
    Posts
    9,668
    Thanks
    298
    Awards
    1
    Quote Originally Posted by dadon
    hi agian!

    how do you fine the coorrdinates where the line 2x+3y=1 meets the curve x(x-y) = 2

    kind regards

    dadon
    Solve 2x+3y=1 for y, plug this y value into x(x-y) = 2 , and solve the resulting equation for x. The use these x values in either of the original equations to get the corresponding y values. I got (6/5, -7/15) and (-1, 1).

    -Dan
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Grand Panjandrum
    Joined
    Nov 2005
    From
    someplace
    Posts
    14,972
    Thanks
    4
    Quote Originally Posted by dadon
    hi agian!

    how do you fine the coorrdinates where the line 2x+3y=1 meets the curve x(x-y) = 2

    kind regards

    dadon
    Rewrite the first equation as

    y=\frac{1-2x}{3}

    Then substitute this for y in the second equation:

    x(x-\frac{1-2x}{3}) = 2

    and solve for x.


    Then substitute the value/s of x that you have
    found back into one of the equations and solve for y.

    RonL
    Follow Math Help Forum on Facebook and Google+

  4. #4
    Member
    Joined
    Apr 2006
    Posts
    201
    Awards
    1

    Thumbs up

    thanks captainblack!
    Follow Math Help Forum on Facebook and Google+

  5. #5
    Member
    Joined
    Apr 2006
    Posts
    201
    Awards
    1

    re:

    sorry captainblack about this but i cant seem to solve for x for the following:

    <br />
x(x-\frac{1-2x}{3}) = 2<br />

    Follow Math Help Forum on Facebook and Google+

  6. #6
    Grand Panjandrum
    Joined
    Nov 2005
    From
    someplace
    Posts
    14,972
    Thanks
    4
    Quote Originally Posted by dadon
    sorry captainblack about this but i cant seem to solve for x for the following:

    <br />
x(x-\frac{1-2x}{3}) = 2<br />

    <br />
x(x-\frac{1-2x}{3})=\frac{x(3x-1+2x)}{3}=\frac{5x^2-x}{3} = 2<br />

    which simplifies to:

    <br />
5x^2-x - 6=0<br />

    which is a quadratic which you can solve using the quadratic formula.

    RonL
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Replies: 5
    Last Post: November 4th 2009, 06:49 PM
  2. Tangent line to a given curve.
    Posted in the Calculus Forum
    Replies: 2
    Last Post: September 2nd 2009, 07:38 AM
  3. Help with curve and line
    Posted in the Pre-Calculus Forum
    Replies: 1
    Last Post: May 19th 2009, 04:37 AM
  4. curve line
    Posted in the Pre-Calculus Forum
    Replies: 5
    Last Post: January 21st 2009, 05:27 PM
  5. Replies: 2
    Last Post: June 10th 2008, 06:33 AM

Search Tags


/mathhelpforum @mathhelpforum