hi agian!

how do you fine the coorrdinates where the line $\displaystyle 2x+3y=1$ meets the curve $\displaystyle x(x-y) = 2 $

kind regards

dadon

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- May 10th 2006, 02:12 AMdadonline meeting curve.
hi agian!

how do you fine the coorrdinates where the line $\displaystyle 2x+3y=1$ meets the curve $\displaystyle x(x-y) = 2 $

kind regards

dadon - May 10th 2006, 03:47 AMtopsquarkQuote:

Originally Posted by**dadon**

-Dan - May 10th 2006, 03:50 AMCaptainBlackQuote:

Originally Posted by**dadon**

$\displaystyle y=\frac{1-2x}{3}$

Then substitute this for $\displaystyle y$ in the second equation:

$\displaystyle x(x-\frac{1-2x}{3}) = 2 $

and solve for $\displaystyle x$.

Then substitute the value/s of $\displaystyle x$ that you have

found back into one of the equations and solve for $\displaystyle y$.

RonL - May 10th 2006, 04:00 AMdadon
thanks captainblack! :)

- May 10th 2006, 05:39 AMdadonre:
sorry captainblack about this but i cant seem to solve for x for the following:

$\displaystyle

x(x-\frac{1-2x}{3}) = 2

$

:( - May 10th 2006, 05:48 AMCaptainBlackQuote:

Originally Posted by**dadon**

x(x-\frac{1-2x}{3})=\frac{x(3x-1+2x)}{3}=\frac{5x^2-x}{3} = 2

$

which simplifies to:

$\displaystyle

5x^2-x - 6=0

$

which is a quadratic which you can solve using the quadratic formula.

RonL