Please help me with the following problems, as I am unsure how to solve them:
1.) log(x+1)^0.25 = 0.50
2.) 2^(x-1) = 3^(x-1)
3.) 600 = 1000(.04^(.3^x))
Your assistance would be much appreciated.
use the rules:
(1)
and
(2)
identify what are your a,b, and c and then just follow the formula
log both sides.2.) 2^(x-1) = 3^(x-1)
you get
then use law (1) from above and solve for x. remember, ln(2) and ln(3) are constants
divide through by 10003.) 600 = 1000(.04^(.3^x))
you get
log both sides, you get:
apply law (1) above:
divide by , you get:
log both sides again:
now apply law (1) again and continue