Please help me with the following problems, as I am unsure how to solve them:

1.) log(x+1)^0.25 = 0.50

2.) 2^(x-1) = 3^(x-1)

3.) 600 = 1000(.04^(.3^x))

Your assistance would be much appreciated.

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- February 24th 2008, 12:09 PMcurrypuffLogarithms
Please help me with the following problems, as I am unsure how to solve them:

1.) log(x+1)^0.25 = 0.50

2.) 2^(x-1) = 3^(x-1)

3.) 600 = 1000(.04^(.3^x))

Your assistance would be much appreciated. - February 24th 2008, 12:32 PMSoroban
Hello, currypuff!

Quote:

We have: .

Then: .

Quote:

Take logs: .

. .

Factor: .

Therefdore: .

Quote:

Divide by 1000: .

Take logs: .

. . Then we have: .

Take logs: .

- February 24th 2008, 12:38 PMJhevon
use the rules:

(1)

and

(2)

identify what are your a,b, and c and then just follow the formula

Quote:

2.) 2^(x-1) = 3^(x-1)

you get

then use law (1) from above and solve for x. remember, ln(2) and ln(3) are constants

Quote:

3.) 600 = 1000(.04^(.3^x))

you get

log both sides, you get:

apply law (1) above:

divide by , you get:

log both sides again:

now apply law (1) again and continue