find the 58th term in the expansion of (2x-3y)^100
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Originally Posted by cm3pyro find the 58th term in the expansion of (2x-3y)^100 we will need this formula From the Binomial Therom this will generate the k+1 th term. so we need n=100 k=57 and evaluating at the above values gives I hope this helps
Last edited by TheEmptySet; February 24th 2008 at 10:12 AM. Reason: Left out a y in the -3y term
(-3)^57 (-3y)^57, correct?
Yes sorry for the typo.
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