1. parabola

i have the equation of a curved edge of the flower bed y=-x^2+2x+3.
The minimum value of y is 4.

But from this im not sure how to calculate the area of the flower bed

Thank you

2. I am assuming you want the area under the curve?.

The vertex of the parabola is at (1,4). It crosses the x axis at -1 and 3

$\int_{-1}^{3}[-x^{2}+2x+3]dx$

3. to find the eqUation of the flower bed i have drawn the graph of y=-x^2+2x+3
it also says ' a gardener is considering a new design for his garden. he has a rectangular lawn measuring 5m by 3m and wants to dig up part of it to include the flower bed.he draws a plan of the lawn and flower bed on the graph paper taking the bottom and left hand edges as the axes and chooses the scale so that 1unit along each axis represents 1metre on the ground . But i need to find the area above the curve