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Math Help - Limit

  1. #1
    Senior Member slevvio's Avatar
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    Limit

    Is it correct to say that \lim_{M\to\infty}\frac{1}{2}tan^{-1}(M^2)=\frac{\pi}{4}?
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  2. #2
    Flow Master
    mr fantastic's Avatar
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    Quote Originally Posted by slevvio View Post
    Is it correct to say that \lim_{M\to\infty}\frac{1}{2}tan^{-1}(M^2)=\frac{\pi}{4}?
    Yes.
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  3. #3
    GAMMA Mathematics
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    Quote Originally Posted by slevvio View Post
    Is it correct to say that \lim_{M\to\infty}\frac{1}{2}tan^{-1}(M^2)=\frac{\pi}{4}?
    Yes! You know that the inverse tangent function limits off at \frac{\pi}{2}, so you just use properties of limits and multiply it by one half.
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