no clue what to do, help please
write an equation for a line tha tasses through (5,4) and is perpinducular to the graph of 2x - 3y = 1
Get those two things and substitute into the general equation
where m is the gradient and is a point on the line.
The point on the line is given on a platter. It's (5, 4).
As for the gradient, you know that it's perpendicular to the line .
(You do know that when two lines are perpendicular, the product of their gradients is equal to -1, right?)
y=mx+b where m is the slope, b is y-intercept.
the line you want has slope -(3/2).
plug in (5,4) to solve for b.
your line is y=-(3/2)x+11.5