no clue what to do, help please
write an equation for a line tha tasses through (5,4) and is perpinducular to the graph of 2x - 3y = 1
thank you!!!1
You need to find two things: the gradient of the line and a point on the line.
Get those two things and substitute into the general equation
$\displaystyle y - y_1 = m(x - x_1)$
where m is the gradient and $\displaystyle \, (x_1, \, y_1)\, $ is a point on the line.
The point on the line is given on a platter. It's (5, 4).
As for the gradient, you know that it's perpendicular to the line $\displaystyle 2x - 3y = 1 \Rightarrow 2x - 1 = 3y \Rightarrow y = \frac{2}{3} x - \frac{1}{3}$.
Therefore: $\displaystyle m \times \frac{2}{3} = -1 \Rightarrow m = .....$
(You do know that when two lines are perpendicular, the product of their gradients is equal to -1, right?)
Two lines are perpendicular to another if their slopes are the negative reciprocals of each other.
y=mx+b where m is the slope, b is y-intercept.
y=(2/3)x-(1/3)
m=2/3
the line you want has slope -(3/2).
y=-(3/2)x+b
plug in (5,4) to solve for b.
4=-(3/2)5+b
b=11.5
your line is y=-(3/2)x+11.5