The functions are: |x+4| and 2|x+4|.
The "standard form" I am talking about involves constants A,B,C, and D: A|B(x-C)|+D.
How can I mold these two functions into a different majestic outcome?
Dear bossbasslol, you have shown with this post that you are not playing with all the marbles available.
Neither $|x+4|$ nor $2|x+4|$ is a function. The first is a simple expression: the distance $x$ is from $-4$.
The second is twice that. There is nothing more to either. Please learn the vocabulary so as not to embarrass yourself.
Ah, I see that my superfluous way of thinking directed my question to a bundle of confusion. To simply fix the |x+4| and 2|x+4| not being functions, add f(x)= to the left of them. Lack of clarity tends to throw off even the brightest of mathematicians. Anyways, I was confused because the "standard form" resembled the vertex formula for a quadratic. I thought that there was some sort of unknown form that applied to functions like these two. Now that I think of it, this seems pretty simple, like what Admin Topsquark suggested. If this is true, I think I can apply this method to functions like f(x)= -2|x+4|+1. Expect more brain-scrambling questions to come!