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Thread: How would I rewrite these functions in "standard form"?

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    How would I rewrite these functions in "standard form"?

    The functions are: |x+4| and 2|x+4|.
    The "standard form" I am talking about involves constants A,B,C, and D: A|B(x-C)|+D.

    How can I mold these two functions into a different majestic outcome?
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    Re: How would I rewrite these functions in "standard form"?

    Quote Originally Posted by bossbasslol View Post
    The functions are: |x+4| and 2|x+4|.
    The "standard form" I am talking about involves constants A,B,C, and D: A|B(x-C)|+D.

    How can I mold these two functions into a different majestic outcome?
    Are you trying to think of something like, for |x + 4|: $\displaystyle (1) |(1)(x - (-4))| + (0)$?

    -Dan
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    Re: How would I rewrite these functions in "standard form"?

    Quote Originally Posted by bossbasslol View Post
    The functions are: |x+4| and 2|x+4|.
    The "standard form" I am talking about involves constants A,B,C, and D: A|B(x-C)|+D.
    How can I mold these two functions into a different majestic outcome?
    Dear bossbasslol, you have shown with this post that you are not playing with all the marbles available.
    Neither $|x+4|$ nor $2|x+4|$ is a function. The first is a simple expression: the distance $x$ is from $-4$.
    The second is twice that. There is nothing more to either. Please learn the vocabulary so as not to embarrass yourself.
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    Re: How would I rewrite these functions in "standard form"?

    Ah, I see that my superfluous way of thinking directed my question to a bundle of confusion. To simply fix the |x+4| and 2|x+4| not being functions, add f(x)= to the left of them. Lack of clarity tends to throw off even the brightest of mathematicians. Anyways, I was confused because the "standard form" resembled the vertex formula for a quadratic. I thought that there was some sort of unknown form that applied to functions like these two. Now that I think of it, this seems pretty simple, like what Admin Topsquark suggested. If this is true, I think I can apply this method to functions like f(x)= -2|x+4|+1. Expect more brain-scrambling questions to come!
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