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Math Help - Exponential model help

  1. #1
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    Post Exponential model help

    I need to solve this problem
    2.5649(1.1096^x)=25
    And I am not sure how to?
    Any help would be greatly appreciated.
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  2. #2
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    Hello, JBondman871!

    Solve for x\!:\;\;2.5649(1.1096^x)\:=\:25

    We have: . 1.1096^x \;=\;\frac{25}{2.5649}

    Take logs: . \ln\left(1.1096^x\right) \;=\;\ln\left(\frac{25}{2.5649}\right)

    Then: . x\cdot\ln(1.1096) \;=\;\ln(25) - \ln(2.5649)

    Finally: . x \;=\;\frac{\ln(25) - \ln(2.5649)}{\ln(1.1096)}


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