1. ## Exponential model help

I need to solve this problem
2.5649(1.1096^x)=25
And I am not sure how to?
Any help would be greatly appreciated.

2. Hello, JBondman871!

Solve for $\displaystyle x\!:\;\;2.5649(1.1096^x)\:=\:25$

We have: .$\displaystyle 1.1096^x \;=\;\frac{25}{2.5649}$

Take logs: .$\displaystyle \ln\left(1.1096^x\right) \;=\;\ln\left(\frac{25}{2.5649}\right)$

Then: .$\displaystyle x\cdot\ln(1.1096) \;=\;\ln(25) - \ln(2.5649)$

Finally: .$\displaystyle x \;=\;\frac{\ln(25) - \ln(2.5649)}{\ln(1.1096)}$