Originally Posted by

**topher0805** Sorry, didn't see the second part of your question!

I assume that $\displaystyle x$ is the length of the one of the sides of the squares that is being cut from the corners? If that is the case:

Volume is equal to $\displaystyle L*W*H$. In this case the L and W will be the same, so we can say that:

$\displaystyle V = L^2*H$

And we know that the length $\displaystyle L$ will be $\displaystyle 16 - x$, so we then have:

$\displaystyle V = (16-x)^2*H$

We also know that the height $\displaystyle H$ will be equal to $\displaystyle x$, so we have that:

$\displaystyle V(x) = x(16-x)^2$