I have no idea how to do the f(37) function f(0) is -3 f(1) is 0 f(5) is -6 f(37) is??? Please help I keep getting that wrong
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$37 = 6\cdot 6 + 1$ So, $f(37) = f(31+6) = f(31) = f(25+6) = f(25) = \cdots = f(1)$ You found out that $f(1) = 0$ above. So, $f(37) = 0$.
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