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Thread: Precalculas difficult Question

  1. #1
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    Precalculas difficult Question

    I don't have a single clue to solve the following question so I post here to seek help.



    Create a polynomial function f(x) with a least two vertical asymptotes, and a non-zero horizontial asymptote.


    Demonstrate how you would find the x-values in which f(x) ≥ 5


    How is this different from finding where f(x) ≥ y ?




    Thank you very much
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  2. #2
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    Re: Precalculas difficult Question

    Quote Originally Posted by luckjoehkg View Post
    I don't have a single clue to solve the following question so I post here to seek help.



    Create a polynomial function f(x) with a least two vertical asymptotes, and a non-zero horizontial asymptote.


    Demonstrate how you would find the x-values in which f(x) ≥ 5


    How is this different from finding where f(x) ≥ y ?




    Thank you very much
    Your question makes no sense. Polynomials don't have vertical asymptotes (and no horizontal ones either.)

    -Dan
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  3. #3
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    Re: Precalculas difficult Question

    Quote Originally Posted by luckjoehkg View Post
    I don't have a single clue to solve the following question so I post here to seek help.
    Create a polynomial function f(x) with a least two vertical asymptotes, and a non-zero horizontial asymptote.
    Demonstrate how you would find the x-values in which f(x) ≥ 5
    How is this different from finding where f(x) ≥ y ?
    Is it possible that instead of polynomial function, it was miss-translated and should be rational function?
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  4. #4
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    Re: Precalculas difficult Question

    If you are, indeed, asked to find a rational function having two vertical asymptotes and a non-zero horizontal asymptote then you want something of the form \frac{1}{(x- a)(x- b)}+ c. The two vertical asymptotes are at x= a and x= b and the horizontal asymptote is y= c which you want to be non-zero.
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    Re: Precalculas difficult Question

    Can anybody kindly explain what is the meaning of f(x) ≥ y ?
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  6. #6
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    Re: Precalculas difficult Question

    You are asked to find those values of x such that f(x) is greater than or equal to 5. You were the one who asked "How is this different from finding where $f(x)\ge y$". The answer to that question is that it is exactly the same with y set equal to 5.
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  7. #7
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    Re: Precalculas difficult Question

    Thank you very much for your help.

    However, would you please explain more why they are the same?

    Thank you very much
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