what is the value of A, B, and C of the partial fraction decomposition of this rational function.
(1x^2-1x+4)/((x+5)(x^2+9))= A/(x+5)+(Bx+C)/(x^2+9)
thanks
You need to find $\displaystyle A,B$ and $\displaystyle C$ such that:
$\displaystyle A(x^2+9)+(Bx+C)(x+5) = x^2-x+4$
You do this by expanding the left hand side collecting the like powers of $\displaystyle x$ and then equating coefficients with those on the right hand side, so:
$\displaystyle A+B=1$
$\displaystyle 5B+C=-1$
$\displaystyle 9A+5C=4$
RonL