Hello,Originally Posted bydadon

to 1): Transform the equation of the line to y = 2x-3. In the intersecting points the y-values of the line and the parabola must be equal:

Solve 2x-3=x^2-2x.

x^2-4x+3=0 ----> x = 3 or x = 1. Plug in these values into the equation of the line and you'll get: A(3,3) and B(1,-1).

to 2)

"collinear" means: forming a line. With 2 points, using the 2-point-formula of the line, you'll get an equation. Plug in the coordinates of the 3rd point and look if they fit into the equation:

Plug in the coordinates of C:

to 3)

(i): x = 0 ----> y = 4, so S(0 , 4)

(ii): y = 0 ----> x = -3, so Z(-3 , 0)

Greetings

EB