Originally Posted by

**otownsend** Hi,

I hope someone can help. So I have the following function h(x) = $\displaystyle f(x)\cdot$ (1/f(x)).

I'm trying to understand if the degree in the function changes why the domain would be different.

For example, let's say that f(x) = $\displaystyle x^2$-25...the domain for h(x) would be x $\displaystyle x \neg$ 5 and $\displaystyle x \neg$ -5.

But what would the domain be if it was to the power of 3 instead of 2? I would think that the domain would be x $\displaystyle \neg 5^(2/3)$, but I don't see this being represented as a hole when I use graphing technology - this makes me skeptical whether my thinking is right about this domain which has a power of 3.

Please let me know.

- Olivia