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Thread: Intergral

  1. #1
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    Intergral

    I need intergral for this

    (2x-4)*(x-1)-2

    the answer is
    (2x-2)- 2 ln (x-1) + c
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  2. #2
    Junior Member Ahri's Avatar
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    Re: Intergral

    $$\int \frac{2x-4}{(x-1)^2} dx = 2 \int \frac{x-2}{(x-1)^2}dx= 2 \int \frac{x-1 -1 }{(x-1)^2}dx = 2 \int \left(\frac{1}{x-1} - \frac{1}{(x-1)^2}\right)dx$$

    Now let $u= x-1$, $du= dx$, can you do the rest?
    Thanks from topsquark
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