# Thread: Transformation of a polynomial function

1. ## Transformation of a polynomial function

Hi,

I hope someone can help. So I developed a polynomial function: f(x) = 1/9(x+3)(x+1)(x-3)(x-1)

I am now trying to horizontally compress this function by a factor of 2. Can someone please confirm with me that the new equation with this transformation applied is f(x) = 1/9(x+1.5)(x+0.5)(x-1.5)(x-0.5)?

If this is wrong, please let me know how I can approach identifying this new equation.

Sincerely,
Olivia

2. ## Re: Transformation of a polynomial function

horizontal compression of $f(x)$ by a factor of two is $\color{red}{f(2x)}$

$f(x) = \dfrac{1}{9}(x+3)(x+1)(x-3)(x-1)$

$\color{red}{f(2x) = \dfrac{1}{9}(2x+3)(2x+1)(2x-3)(2x-1)}$

3. ## Re: Transformation of a polynomial function

Thanks for your help