I think I might have to subtract?
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You think? You should already have learned the "laws of exponents": , , and .
Is the answer 8^2x/2^4x=4^-2x?
Originally Posted by dtdj13 Is the answer 8^(2x)/2^(4x) = 4^(-2x)? No ... oh,yea ...parentheses! $\dfrac{8^{2x}}{2^{4x}} = \dfrac{(2^3)^{2x}}{2^{4x}} = \dfrac{2^{6x}}{2^{4x}}$ finish it ...
it is a multiple choice question the answers are 2^x, 4^X, 2^-2x,4^-2x i got 2^2x which isn't one of the choices.
Again using the "laws of exponents", . Learn the laws of exponents!
Originally Posted by dtdj13 it is a multiple-choice question the answers are 2^x, 4^X, 2^-2x,4^-2x i got 2^2x which isn't one of the choices. No, use parentheses (as in the following): ... the answers are 2^x, 4^x, 2^(-2x), 4^(-2x). I got 2^(2x), which isn't one of the choices. Suppose the actual answer is equivalent to 2^(2x), which is what you figured. Can you convert that to one of the answer choices?
Originally Posted by dtdj13 it is a multiple choice question the answers are 2^x, 4^X, 2^(-2x),4^(-2x) i got 2^(2x) which isn't one of the choices. parentheses ... parentheses ... parentheses ... parentheses ... btw, did I say ... parentheses ... ?
is the answer equivalent to 4^x? or is it 2^x btw I don't how to use parentheses outside of using them in a calculator
put away the calculator ... $(\color{red}{2^2})^x = (\color{red}{4})^x = 4^x$
The conventions for use of parentheses in a calculator and anywhere else are the same. Failure to use parentheses where they are needed will cause you to get erroneous answers.