My teacher told the tutors at my school not to help us on are homework and I don't have enough money to get a tutor so this is my only hope. I don't how to start on this.
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$e^x-6e^{-x}-1=0$ Multiply every term by $e^x$ ... $e^{2x}-6-e^x=0$ $e^{2x}-e^x-6=0$ let $u=e^x$ and solve the resulting factorable quadratic equation. Got you started ... finish it.
I think I got it right
Originally Posted by dtdj13 I think I got it right uh, no ... you didn't.
$\left| \begin{array}{l}e^{2x}-e^x-6=0\\(e^x-3)(e^x+2)=0\\e^x=3~~\&~~e^x=-2\end{array} \right.$ But it is impossible for $e^x$ to be negative, so there is but one answer: $x=\log(3)$.