The triangle ABC is a right triangle with legs BC=3 and AC=4. The two angle trisectors of angle C intersect the hypotenuse. The longer of these trisectors has length (a(√(3))+b)/c), where gcf(a,b,c)=1
Even some preliminary explanation would help great deals. I need to figure it out tonight.
Here's an easy but tedious method:
Originally Posted by LordHz
C (0,0) A (4,0) B (0,3) Call the required length CP
equation of line throug C and P is ..... equation of line through A and B is .....
Solve simultaneously to find P then use Pythagoras to find length CP.
Or use some clever geometry.....