The triangle ABC is a right triangle with legs BC=3 and AC=4. The two angle trisectors of angle C intersect the hypotenuse. The longer of these trisectors has length (a(√(3))+b)/c), where gcf(a,b,c)=1

Evaluate 15a-6b+32c.

Even some preliminary explanation would help great deals. I need to figure it out tonight.