Solve: (log3 X)^2 + log3 X^2 = 8
Follow Math Help Forum on Facebook and Google+
let $u = \log_3{x}$ ... $u^2 + 2u - 8 = 0$ $(u+4)(u-2) = 0$ $u = -4 \implies \log_3{x} = -4 \implies x = ?$ $u = 2 \implies \log_3{x} = 2 \implies x = ?$
Thank you so much - really helped ����