What is the first step in factoring the following problem?
64 (x - a)^4 - x + a
(x - a)[64 (x - a)^3 - 1]
We use a^3 – b^3 = (a – b)(a^2 + ab + b^2).
Let a = (x - a)
Let b = 1
(x - a - 1)[(x - a)^2 + (x - a)(1) + (1)^2]
(x - a - 1)[64 (x - a)^2 + (x - a) + 1
Putting it all together I got the following:
(x - a)[(x - a - 1)64 (x - a)^2 + (x - a) + 1]
Is this right?