Given log_{18}6 = a, find log_{18}16 in terms of a. I have looked at some other problems and I can't figure out how this would even work.
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Originally Posted by jstr99 Given log_{18}6 = a, find log_{18}16 in terms of a. I have looked at some other problems and I can't figure out how this would even work. There are infinitely many correct answers. $a=\frac{\log(6)}{\log(18)}~\&~b=\frac{\log(16)}{\ log(18)}$ implies that $b=\frac{a\log(16)}{\log(6)}=a\log_6(16)$
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