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Thread: Grouping Method

  1. #1
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    Grouping Method

    Factor By grouping.

    100 (h + 1)^3 - (h + 1)^5

    (h + 1)^3 [100 - (h + 1)^2]

    (h + 1)^3 [(10 - (h + 1)(10 + (h + 1)]

    Is this correct?
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  2. #2
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    Re: Grouping Method

    yes it is
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    Re: Grouping Method

    Quote Originally Posted by mathdad1965 View Post
    Factor By grouping.

    100 (h + 1)^3 - (h + 1)^5

    (h + 1)^3 [100 - (h + 1)^2]

    (h + 1)^3 [(10 - (h + 1)(10 + (h + 1)]

    Is this correct?
    Quote Originally Posted by sakonpure6 View Post
    yes it is
    No, it is not.

    1) There are missing grouping symbols. 2) It hasn't been factored completely and simplified, such as like terms combined.


    100(h + 1)^3 - (h + 1)^5 =

    (h + 1)^3*[100 - (h + 1)^2] =

    (h + 1)^3* [10 - (h + 1)][10 + (h + 1)] =

    (h + 1)^3*[10 - h - 1][10 + h + 1] =

    (h + 1)^3*(9 - h)(11 + h) =

    (9 - h)(11 + h)(h + 1)^3
    Last edited by greg1313; Jan 3rd 2017 at 11:59 AM.
    Thanks from mathdad1965
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  4. #4
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    Re: Grouping Method

    Quote Originally Posted by sakonpure6 View Post
    yes it is
    Are you sure?
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  5. #5
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    Re: Grouping Method

    Quote Originally Posted by greg1313 View Post
    No, it is not.

    1) There are missing grouping symbols. 2) It hasn't been factored completely and simplified, such as like terms combined.


    100(h + 1)^3 - (h + 1)^5 =

    (h + 1)^3*[100 - (h + 1)^2] =

    (h + 1)^3* [10 - (h + 1)][10 + (h + 1)] =

    (h + 1)^3*[10 - h - 1][10 + h + 1] =

    (h + 1)^3*(9 - h)(11 + h) =

    (9 - h)(11 + h)(h + 1)^3
    You are right. The textbook answer is your answer.
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