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Thread: Factor By Grouping

  1. #1
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    Factor By Grouping

    Factor By grouping.

    a^2 x + bx - a^2 z - bz

    a^2 x + bx = x (a^2 + b)

    - a^2 z - bz = -z (a^2 + b)

    My answer is (x - z)(a^2 + b).

    Is this correct?
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  2. #2
    Super Member sakonpure6's Avatar
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    Re: Factor By Grouping

    Yes that is correct, you can check your self too, just multiply out the bracketed terms!
    Thanks from mathdad1965
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  3. #3
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    Re: Factor By Grouping

    Good to know that I did not mess this one up.
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  4. #4
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    Re: Factor By Grouping

    Quote Originally Posted by mathdad1965 View Post
    a^2 x + bx - a^2 z - bz

    My answer is (x - z)(a^2 + b).
    A quick way to "see" if correct is assign "easy to work with"
    values to the variables; like with your problem:
    a=1, b=2, x=3, z=4.
    Substitute in both the original and the answer:
    if both same, then "SUCCESS!".
    Thanks from USNAVY and mathdad1965
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    Re: Factor By Grouping

    Quote Originally Posted by DenisB View Post
    A quick way to "see" if correct is assign "easy to work with"
    values to the variables; like with your problem:
    a=1, b=2, x=3, z=4.
    Substitute in both the original and the answer:
    if both same, then "SUCCESS!".
    I am sure he will love this trick.
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  6. #6
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    Re: Factor By Grouping

    Quote Originally Posted by DenisB View Post
    A quick way to "see" if correct is assign "easy to work with"
    values to the variables; like with your problem:
    a=1, b=2, x=3, z=4.
    Substitute in both the original and the answer:
    if both same, then "SUCCESS!".
    Thank you very much.
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