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**HallsofIvy** If you do not know the definitions of the words and symbols it is tricky. If you **do** know what this means then it is very easy. First, you would know that |x| is x if x is positive and -x if x is negative. In particular, if x+ pi/2 is positive, then |x+ pi/2| is x+ pi/2 so |x+ pi/2|> 1 becomes x+ pi/2> 1. If x+ pi/2 is negative then |x+ pi/2|= -(x+ pi/2) so |x+ pi/2|> 1 becomes -(x+ pi/2)> 1 and then x+ pi/2< -1.

Mark the point 1- pi/2 (about -.57) on the number line. One part of the solution set is all number beyond that. Now mark -1- pi/2 (about -2.57). The rest of the solution set is all numbers lower than that. The closed interval from -1-pi/2 to 1- pi/2 give everything **not** in the solution set.