remember the domain of a function is the set of all input values that we can plug in, in this case, that is the x-values. so what x-values CAN'T we plug in? the domain is all x's except those.

first thing we notice, this is a fraction, so the denominator cannot be zero. so one x we cannot be is the one that makes the denominator zero. now for the square root, what is being square rooted must be greater than or equal to zero. the first condition prevents us from being 0, so the domain is given by all real x such that x - 7 > 0. so what is your solution? can you write it in interval form?

these are all polynomials. their domains are all real xAlso what would be the domains of:

(x^2)-13*x+x+8

(x^2)-13*x-(x+8)

[(x^2)-13*x]*(x+8)

consider what i said on the first problem and try thisand also the domain of f+g

f-g

fg

given that f(x)=(square root)8+x(end square root) and g(x)=(square root)8-x(end square root)