Plot the point z on a graph.
Reflect that point in the real axis; that is z conjugate.
Now divide by the absolute value of z squared.
Using , geometrically show how you would construct .
NOTE z* means the conjugate of z.
I have no idea. I know how to show it algebraically, since we'd have:
Then, multiply the left side by the complex conjugate and we get the right hand side...
How'd I show this geometrically?
So if we have our axis', we'd have:
ib on the vertical axis (above 0)
-ib on the vertical axis (below 0)
And we'd have a somewhere on the traditional x-axis (greater than 0)
So then a - ib will put us in the 4th quadrant, and that is our conjugate...
How do I graph a^2 + b^2 and then divide this by the point I already created from the conjugate?
of course, this works if and are not both zero. if , then